The greatest standard deviation would most likely be found in which of the following?

This course is designed to acquaint the student via the principles of descriptive and also inferential statistics. Topics will certainly include: types of data, frequency distributions and also histograms, procedures of central tendency, steps of variation, probability, probability distributions consisting of binomial, normal probability and also student's t distributions, conventional scores, confidence intervals, hypothesis experimentation, correlation, and direct regression analysis. This course is open up to any type of student interested in general statistics and also it will include applications pertaining to students majoring in athletic training, pre-nursing and company.

You watching: The greatest standard deviation would most likely be found in which of the following?


In an​ editorial, the Poughkeepsie Journal published this​ statement: "The median price – the price exactly in between the highest and also lowest – ..." Does this statement correctly explain the​ median? Why or why​ not?


Which of the following is always​ true?

A. File skewed to the best have actually a longer left tail than ideal tail.

B. In a symmetric and​ bell-shaped distribution, the​ expect, median, and also mode are the exact same.

C. For skewed​ information, the mode is farther out in the much longer tail than the median.

D. The mean and median must be provided to recognize the form of the distribution.


Pennies made prior to 1983 are​ 97% copper and​ 3% zinc, whereas pennies made after 1983 are​ 3% copper and​ 97% zinc. Listed below are the weights​ (in grams) of pennies from each of the two time durations.

Find the intend and median for each of the two​ samples.

Does tright here appear to be a considerable difference in the​ means?


The expect weight of the pennies made before 1983 is 3.1133 grams.

The median weight of the pennies made before 1983 is 3.10645 grams.​

The mean weight of the pennies made after 1983 is 2.4926 grams.​

The median weight of the pennies made after 1983 is 2.49315 grams.​

​Yes, because the distinction in the implies is more than​ 5%.


Listed below are head injury measurements from small cars that were tested in crashes. The measurements are in​ "hic," which is a measurement of a standard​ "head injury​ criterion," (lower ​ "hic" worths correspond to safer​ cars). The listed values correspond to cars​ A, B,​ C, D,​ E, F, and​ G, respectively.

Find the a.​ mean, b.​ median, c.​ midselection, and also d. mode for the information.

e. Which auto appears to be the​ safest?

f. Based on these limited​ outcomes, do little cars appear to have about the very same risk of head injury in a​ crash?


a. The expect is 417.7.​

b. The median is 392.​

c. The midselection is 425.

d. There is no mode.

e. auto E

f. No, bereason the information values differ dramatically.


Because the mean is incredibly sensitive to extreme​ worths, it is not a resistant meacertain of center. The trimmed mean is more resistant. To uncover the​ 10% trimmed suppose for a data​ set, first arrange the data in​ order, then delete the bottom​ 10% of the values and also the top​ 10% of the​ values, then calculate the suppose of the remaining values.

For the following​ credit-rating scores, uncover ​(a) the​ suppose, (b) the​ 10% trimmed​ suppose, and​ (c) the​ 20% trimmed mean.

How carry out the results​ compare?


a. The expect is 720.5.

b. The​ 10% trimmed suppose is 729.3.​

c. The​ 20% trimmed mean is 734.3.

The circulation of the data appears to be skewed to the left because the results appear to present a trfinish of boosting values as the portion of trim boosts.


Listed listed below are the durations​ (in hours) of an easy random sample of all flights of an area shuttle.

Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midvariety for the given sample information.

(e) Is there a duration time that is very​ unusual? How could that duration time be​ explained?


a. The suppose is 218.7 hrs.​

b. The median is 239.0 hours.

c. The mode is 239 hours.

d. The midarray is 192.0 hrs.

e. Yes, the time of 0 hours is incredibly inexplicable. It can reexisting a flight that was aborted.


An experiment was conducted to determine whether a deficiency of carbon dioxide in the soil affects the phenotype of peas. Listed below are the phenotype codes wbelow 1 amounts to smooth dash yellow​, 2 equates to smooth dash green​, 3 equals wrinkled dash yellow​, and 4 equates to wrinkled dash green.

Find the​ (a) suppose,​ (b) median,​ (c) mode, and​ (d) midvariety for the offered sample information.

(e) Do the results make​ sense?


a. The intend phenokind code is 2.9.​

b. The median phenokind code is 3.0.

c. The mode phenoform code is 3.

d. The midrange of the phenokind codes is 2.5.

e. Only the mode renders feeling since the data is nominal.


Refer to the data set of​ times, in​ minutes, required for an plane to taxi out for​ takeoff, detailed below.

Find the mean and median.

How is it helpful to find the​ mean?


The suppose of the data set is 28.5 minutes.​

The median of the data collection is 27.0 minutes.

The suppose taxi out time is vital for calculating and also scheduling the arrival time.


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Below are the range and typical deviation for a set of information.

Use the range dominance of thumb and compare it to the conventional deviation noted below.

Does the variety preeminence of thumb develop an acceptable​ approximation? Suppose a researcher deems the approximation as acceptable if it has an error much less than​ 15%.


The estimated traditional deviation is 0.730

No, bereason the error of the array dominion of​ thumb"s approximation is greater than​ 15%.


Cans of consistent soda have actually quantities via a intend of 12.01 oz and also a traditional deviation of 0.11 oz.

Is it inexplicable for a deserve to to contain 12.11 oz of​ soda?


Minimum​ "usual" value = 11.79 oz

minimum​ "usual" worth = ​(mean) 2 x (traditional ​deviation

Maximum​ "usual" value = 12.23 oz

minimum​ "usual" value = ​(mean) + 2 x (standard ​deviation)

No, because it is in between the minimum and also maxmum "usual" worths.

See more: Lesson 12: Correlation & Simple Linear Regression


Cans of constant soda have volumes with a mean of 12.24 oz and also a standard deviation of 0.11 oz.

Is it unexplained for a have the right to to contain 12.58 oz of​ soda?


Minimum​ "usual" value = 12.02 oz

minimum​ "usual" value = ​(mean) 2 x (typical ​deviation

Maximum​ "usual" worth = 12.46 oz

minimum​ "usual" value = ​(mean) + 2 x (conventional ​deviation)

Yes, because it is larger than the maximum "usual" value.


Identify the icons supplied for each of the​ following: (a) sample standard​ deviation; (b) populace standard​ deviation; (c) sample​ variance; (d) populace variance.


a. The symbol for sample conventional deviation is s.

b. The symbol for populace typical deviation is σ .

c. The symbol for sample variance is s²

d. The symbol for population variance is σ² .


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The trfinish of thinner beauty pageant winners has actually produced charges that the challenge urges unhealthy diet behavior among young women. Listed listed below are body mass indexes​ (BMI) for beauty pageant winners from 2 different time periods.

Find the coreliable of variation for each of the two sets of​ data.

Is tbelow a distinction in variation between the two data​ sets?


The coeffective of variation for the​ BMI"s of beauty pageant winners from the 1920s and 1930s is 7.50​%.

CV = stand also dev ÷ mean x 100%

The coefficient of variation for the​ BMI"s of recent beauty pageant winners is 6.37​%.

Tright here is no considerable distinction in the variations.


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Waiting times​ (in minutes) of customers at a bank wbelow all customers enter a solitary waiting line and a bank wright here customers wait in individual lines at 3 various teller windows are noted listed below.

Find the coreliable of variation for each of the two sets of​ information.

Is there a distinction in variation in between the 2 data​ sets?


The coefficient of variation for the waiting times at Bank A is 6.41​%.

CV = stand also dev ÷ expect x 100%

The coeffective of variation for the waiting times at the Bank B is 24.61​%.

The waiting times at Bank A have significantly much less variation than the waiting times at Bank B.


Which of the adhering to is NOT a home of the standard​ deviation?

A. When comparing variation in samples through very different​ implies, it is excellent practice to compare the 2 sample traditional deviations.

B. The value of the conventional deviation is never before negative.

C. The conventional deviation is a measure of variation of all data values from the expect.

D. The units of the conventional deviation are the very same as the systems of the original data.


A. When comparing variation in samples through very different​ means, it is excellent exercise to compare the 2 sample typical deviations.


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Listed listed below are the gross amounts​ (in millions of​ dollars) earned in box office receipts for a recent movie. The amounts are noted in order for the initially 14 days of the movies release.

Find the​ variety, variance, and also typical deviation of the data set.

If you invested in this​ movie, what characteristic of the data collection would you care about​ many, and also is it a meacertain of center or​ variation?


The range of the sample information is 55 million dollars.

The variance of the sample data is 366.8 million dollars².

The typical deviation of the sample information is 19.2 million dollars.

The gross from opening day and the rate of decrease. The procedures of center and variation are much less vital.


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Listed below are the quantities of mercury​ (in components per​ million, or​ ppm) uncovered in tuna sushi sampled at various stores.

Find the​ variety, variance, and standard deviation for the set of data.

What would be the values of the actions of variation if the tuna sushi included no​ mercury?


The selection of the sample data is 0.48 ppm.

Sample variance = 0.029 ppm²

Sample typical deviation = 0.171 ppm

The actions of variation would certainly all be 0.


Heights of men on a baseround team have actually a​ bell-shaped circulation via a mean of 182 cm and also a traditional deviation of 7 cm.

Using the empirical​ rule, what is the approximate percentage of the males in between the following​ values?

a. 168 cm and 196 cm

b. 161 cm and also 203 cm


a. 95​% of the men are between 168 cm and also 196 cm.

b. 99.7​% of the men are between 161 cm and 203 cm.

one typical deviation from the expect accounts for about 68% of the set two typical deviations from the intend account for around 95% 3 conventional deviations from the expect account for around 99.7%.
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The adhering to are amounts of time​ (minutes) spent on hygiene and grooming in the morning by survey respondents.

Determine the​ 5-number summary and construct a boxplot for the data provided below.


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The​ 5-number summary is 6​, 11​, 18.5​, 37​, 62.


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Below are 36 sorted eras of an acting award winner.

Find P70 utilizing the technique presented in the textbook.


P70 = 66

L = k ÷ 100 x n

70 ÷ 100 x 36 = 25.2 (round up)

What is the Lth = 26th worth in the sorted​ list? 66

What is the next worth in the sorted​ list? 66

P75 = (66 + 66) ÷ 2 = 66


IQ scores are measured via a test designed so that the mean is 103 and the standard deviation is 13. Consider the group of IQ scores that are unexplained.

What are the z scores that separate the inexplicable IQ scores from those that are​ usual?

What are the IQ scores that sepaprice the unexplained IQ scores from those that are​ usual?(Consider a value to be unusual if its z score is less than –2 or greater than​ 2.)


The reduced z score boundary is –2.

The greater z score boundary is 2.

The lower bound IQ score is 64.

(lower z score x conventional deviation) + mean

The better bound IQ score is 136.

(greater z score x standard deviation) + mean


If your score on your next statistics test is converted to a z​ score, which of these z scores would you​ prefer: –2.00, –1.00, ​0, 1.00,​ 2.00? Why?


The z score of 2.00 is most preferable because it is 2.00 conventional deviations over the expect and would certainly correspond to the highest of the 5 various possible test scores.


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Use the very same scale to construct boxplots for the ages of the ideal actors and also finest actresses from the accompanying data sets.

Use the boxplots to compare the two data sets.


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Actors: 27, 37, 43, 50, 76

Actresses: 21, 28, 33, 39, 82

Although actresses incorporate the oldest​ age, the boxplot representing actresses shows that they have actually ages that are generally reduced than those of actors.


Which is relatively​ better: a score of 76 on a psychology test or a score of 45 on an economics​ test? Scores on the psychology test have actually a expect of 89 and a conventional deviation of 5. Scores on the economics test have actually a intend of 55 and also a standard deviation of 7.

See more: What Is Not A Benefit Of Mapping A Chapter Prior To Fully Reading It?


The economics test score is relatively much better because its z score is higher than the z score for the psychology test score.