Having done poorly on their math final exams in june six students

2 Of the complying with cases, decide which need to be analyzed using one-sample matched pair procedure and which must be analyzed utilizing two-sample procedures? A pharmaceutical firm desires to test its new weight-loss drug. Before providing the drug to a random sample, company researchers take a weight measurement on each perboy. After a month of utilizing the drug, each person’s weight is measured aobtain. Matched pair

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3 Of the adhering to situations, decide which have to be analyzed utilizing one-sample matched pair procedure and which must be analyzed using two-sample procedures? A researcher desires to know if a populace of brvery own rats on one city has a better mean size than a population in an additional city. She randomly selects rats from each city and procedures the lengths of their tails. Two independent samples

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4 Of the adhering to situations, decide which have to be analyzed using one-sample matched pair procedure and which should be analyzed using two-sample procedures? A researcher desires to know if a new vitamin supplement will make the tails of brown rats prosper longer. She takes 50 rats and divides them into 25 pairs matched by sex and also age. Within each pair, she randomly selects one rat to obtain the new vitamin. After six months, she procedures the size of the rat’s tail. Matched pair

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5 Two independent samplesOf the adhering to cases, decide which need to be analyzed utilizing one-sample matched pair procedure and also which must be analyzed making use of two-sample procedures? A college wants to see if there’s a difference in time it took last year’s course to find a job after graduation and the moment it took the course from five years earlier to find work after graduation. Researchers take a random sample from both classes and also measure the number of days between graduation and initially day of employment Two independent samples

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6 Matched Pairs (Special kind of one-sample means)

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7 2) The sample circulation of differences is around normalDifferences of Paired Means (Matched Pairs) CONDITIONS: 1) The samples are paired. The sample distinctions can be perceived as a random sample from a populace of differences. 2) The sample distribution of differences is roughly normal - the populaces of distinctions is well-known to be normal, or - the variety of sample distinction is huge (n  30), or - graph data to show approximately normal 3) 10% ascendancy – The sample of distinctions is not more than 10% of the populace of distinctions.

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8 Differences of Paired Means (Matched Pairs)

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9 Hypothesis Statements:Differences of Paired Means (Matched Pairs) Parameter: md = true expect difference in … Hypothesis Statements: H0: md = hypothesized value Ha: md Ha: md> hypothesized value Ha: md ≠ hypothesized value

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10 Differences of Paired Means (Matched Pairs)Hypothesis Test:

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11 #18 Summer School. Having done poorly on their Math final exams in June, 6 students repeat the course in summer institution and take one more exam in August.


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If we consider these students to be representative of all students that can attfinish this summer school in various other years, carry out these outcomes administer evidence that the routine is worthwhile? June 54 49 68 66 62 Aug. 50 65 74 64 72

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12 Ho: μd = 0 Page 590: 18 Parameters and Hypothesesμd = the true mean difference in scores between June and August for students who recurring the course in summer college Ho: μd = 0 Ha: μd > 0

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13 Assumptions (Conditions)1) The samples need to be paired and random. The samples are from the very same student so they are paired and we will assume the sample differences are a random sample of the populace of differences.. 2) The sample distribution should be about normal. The normal probcapacity plot is sensibly straight and the boxplot mirrors no outliers, so we will assume that the sample distribution of differences is approximately normal. 3) The sample should be much less than 10% of the population. The populace must be at leastern 60 students, which we will certainly assume. 4)  is unknown Because the problems are met, a t-test for the matched pairs is correct.

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14 Calculations 5.333 7.4475 5.333 7.4475  = 0.05

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a, I fail to reject the null hypothesis at the .05 level. Conclusion:" > 15 Decision: Because p-value > a, I fail to disapprove the null hypothesis at the .05 level. Conclusion: Tbelow is not enough proof to indicate that the true suppose difference in scores is different from June to August. This suggests that regime may not be worthwhile.

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a, I fail to refuse the null hypothesis at the .05 level. Conclusion:" title="Tbelow is not enough proof to indicate that the true expect difference in scores is various from June to August. This argues that program may not be worthwhile.">